to all you math wizards out there (Help a guy out)

[Dragnskull]

hey guys, leme give u a lil idea of wuts goin on...i failed Algebra II A last year...so im stuck taking it this year...ez 'nuff to understand... well were in the second six weeks, friday is the last day of it (weve had 1 outa 6 report cards, number 2 is about to come out) and im failing the class... were takign a test over 2 things tomorow, and it will replace the lowest testgrade of this six weeks (if we do good on it) and well, i dont know the material...its hard as **** fo rme...i can do the simple stuff, but the harder stuff beats me down =/ so i was hopeing you great guys here at bf would be willin to help me, my fait rests in you guys's hands =/ so plz help if you can

i need to understand this crap for the test tomorow...

first off, Radicals

i need to learn how to do things like the followign:

Square root of 48x squared

3 square root of 2 (square root of 18 - 5 square root 12)

5 over 4 + square root 3

-3 square root -144

Then, i need to learn how to do invisible numbers...i can kinda do them but not fully...

where i = square root of (-1)

3 over 2 + 3i

4 + i over 4 - i

er...

4 + i
--------
4 - i

well yeah if anyone knows how to do this stuff and u can help me out please do, cause i could really use the help

btw: i need this soon, like before 10 pm, its around 8 now =/

sorry for makin this so close to deadline but i just got the idea to do this...thanks again.

[Andrew]

Originally Posted by DragnSkull

Square root of 48x squared

Isn't a square root of a squared number itself?

[Dragnskull]

uh...square root = where like

Sr = squre root

sr25 = 5
cause 5 x 5 = 25

sr = where you have to find a number that multiplyd by itself = the number givin

say ur givin the sr of a

what your tryin to find, is the answer (b) where b x b = a

[dathief]

for the invis numbers... u learn that in grade 8... i just learned that like...last week...i kinda forgot... im in Math 8 Advanced Placement

isubscribt one is i think 1
and I 2 is um...gotta review my notes...will help u later hommie G
-peace

[x42bn6]

I'm going to put 's()' as the square root.....

Originally Posted by DragnSkull

Square root of 48x squared

s(48)*x

Originally Posted by DragnSkull

3 square root of 2 (square root of 18 - 5 square root 12)

3s(2)(s(18)-5s(12))
=3s(2)(s(2*9)-5s(3*4))
=3s(2)(3s(2)-10s(3))
=18-30s(2)s(3)

Originally Posted by DragnSkull

5 over 4 + square root 3

Can't work out as I don't know what denominators or numberators.....

Originally Posted by DragnSkull

-3 square root -144

-3s(12i)

If i²=-1, i=s(-1), and s(-144)=s(-1*144)=12s(-1)=12i

Originally Posted by DragnSkull

4 + i over 4 - i

Congugate the number.
=((4+i)(4+i))/((4-i)(4+i))
=(16+8i+i²)/(16-i²)
=(16+8i+-1)/(16--1)
=(15+8i)/15

Basically, i²=-1, i=s(-1).*

[drax]

Once again x42bn6 comes to the rescue!

[x42bn6]

Originally Posted by drax

Once again x42bn6 comes to the rescue!

I have a reason to abuse my Further Maths knowledge, IMO.*

[Dragnskull]

x42bn6 : thanks man...appriciate the help, but uh, ur a bit late =/ i took the math test about an hour ago, hope i did good =/

[_CM]

lets see

i^2 = -1

i thought a squared number mustn't be negative maybe i'm just too dumb for this

[Korittke]

i thought you were talking about the 5th sr

[l33t bunny master]

-3 square root -144

no that would be..

-3is(144)
-3ix12 = -36i

[x42bn6]

Originally Posted by l33t bunny master

no that would be..

-3is(144)
-3ix12 = -36i

Meh, same difference.

@coolmission: This is a complex number (not invisible like some Americans say), where i is the square root of -1. Each complex number has a real and imaginary part, where it is denoted commonly by z. So if z=2-2i, Re(z)=2, Im(z)=-2. (Real and Imaginary components respectively.

You use complex numbers in electronics, and to prove some indices rule.

You can't use inequalities with complex numbers though.

The only hard thing about complex numbers is probably when they are in polar form. Then that gets hard, with arg(z) and stuff.*

[_CM]

the luxembourgish system is so different ... holy shit ....

[OMGLOLWTFPWN]

For the complex numbers it start off with
i= sqroot -1
i^2 = -1
i^3 =i^2(i)=-i
i^4 = i^2(i^2)= -1(-1)=1

Then the pattern repeats, i, -1, -i, 1

[x42bn6]

Originally Posted by coolmission

the luxembourgish system is so different ... holy shit ....

Complex numbers are a part of all A Level and equivalent subjects of Further Maths. It might be called Applied Maths.*

[Sakuhta]

Originally Posted by DragnSkull

uh...square root = where like

Sr = squre root

sr25 = 5
cause 5 x 5 = 25

sr = where you have to find a number that multiplyd by itself = the number givin

say ur givin the sr of a

what your tryin to find, is the answer (b) where b x b = a

What he's trying to tell you is

SR(48^2)

SR = Finds the Square

^2 squares it

SR(48^2) is 48.

[x42bn6]

Originally Posted by Sakuhta

What he's trying to tell you is

SR(48^2)

SR = Finds the Square

^2 squares it

SR(48^2) is 48.

He said, "Square root of 48x squared."

[Sakuhta]

Ah! 6x, if you're rounding it.

[Ntrik_]

why are you guys still responding when y237gc5 already said the answer?

[Sakuhta]

Because read the post again, he didn't answer the first problem.