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Old 12-19-2005, 04:20 PM   #1 (permalink)
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math question!

How do I do this?!



I need to slove for y (the distance between the edge of the elipse and the centre of the circle) and the percent the blue, green and red colours take up in the elipse and the area of the triangle. The picture is small so I'll list the given stuff, the angle on the left side of the triangle is 45.93895 degrees and the right edge of the triangle has a length of 2 metres.
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Old 12-19-2005, 04:38 PM   #2 (permalink)
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It appears to be trig.
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Old 12-19-2005, 08:27 PM   #3 (permalink)
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Originally Posted by Ethanael
It appears to be trig.
lol..maybe i'm wrong but that doesn't look at all like trig. It looks like geometry.
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Old 12-19-2005, 09:38 PM   #4 (permalink)
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No it looks like a elipse with a triangle in it.
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Old 12-19-2005, 09:42 PM   #5 (permalink)
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It looks like I have failed math for the past 4 years.
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Old 12-20-2005, 07:09 AM   #6 (permalink)
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Let Zerglite do it.
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Old 12-20-2005, 07:30 AM   #7 (permalink)
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How about the rest of the information given? Like the top angle, and the line's distance seperating the blue and green? Also, write the left angle out to every decimal that they give you.
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Old 12-20-2005, 07:34 AM   #8 (permalink)
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Well, it looks like the center of the triangle is also the center of the ellipse, and that the ellipse radius whose length you have to determine makes a 90º angle with the triangle hipotenuse. We know that the hipotenuse length = 2/sin(45.93895). Using pithagoras theorem we can find the low side of the triangle, and then its area. I'll continue with it later on, gotta eat lunch now :o
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Old 12-20-2005, 02:06 PM   #9 (permalink)
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I need some measurements and angles so trigenomitry can be done.
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Old 12-20-2005, 02:15 PM   #10 (permalink)
 
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y = any real number
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Old 12-20-2005, 02:20 PM   #11 (permalink)
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I've never seen that in geometry so its definitely trigonomitry.
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Old 12-20-2005, 02:21 PM   #12 (permalink)
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Maybe it would also help if he TYPED THE VALUES A LITTLE BIGGER KTHX!
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Old 12-20-2005, 04:20 PM   #13 (permalink)
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Quote:
Originally Posted by Hellwolf_36
Maybe it would also help if he TYPED THE VALUES A LITTLE BIGGER KTHX!


DUUUR I typed them out in the paragraph DURR
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Old 12-20-2005, 05:42 PM   #14 (permalink)
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DUUUR IM A EFFIN WETARD DUUUR

and if you guys really know geometry and trig, you should be able to get the rest of the angles of the triangle.


I don't remember how/when to do Cons and all that other crap, so I can't really figure tis out right now.

That is just a ****ed up angel, 49.3474123546259396247
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Old 12-20-2005, 05:59 PM   #15 (permalink)
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bah, delete this
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Old 12-21-2005, 12:23 AM   #16 (permalink)
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Quote:
Originally Posted by -Azrael666-
How about the rest of the information given? Like the top angle, and the line's distance seperating the blue and green?
Quote:
Originally Posted by Hellwolf_36
Maybe it would also help if he TYPED THE VALUES A LITTLE BIGGER KTHX!
Quoted for truth.

Quote:
Originally Posted by kirby2
DUUUR I typed them out in the paragraph DURR
He meant all of them, as in, the ones you obviously missed. DURR.
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Old 12-21-2005, 01:22 AM   #17 (permalink)
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Quote:
Originally Posted by -Azrael666-
Quoted for truth.


He meant all of them, as in, the ones you obviously missed. DURR.

DURR 180 -90 -the other one = the top angle, to hard for me to figure out!?!
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Old 12-21-2005, 02:29 AM   #18 (permalink)
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Is the centre of the circle and the centre of the ellipse the same?*
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Old 12-21-2005, 08:42 AM   #19 (permalink)
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Quote:
Originally Posted by kirby2
DURR 180 -90 -the other one = the top angle, to hard for me to figure out!?!
You didn't give the angle to all its decimal places, or the distance of the line seperating the green and blue areas, like I said. You should learn to read before engaging in a text-based discussion.

And remember, you're the idiot who can't do ninth grade math.
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Old 12-21-2005, 08:21 PM   #20 (permalink)
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DURR 180 -90 -the other one = the top angle, to hard for me to figure out!?!
In the image there is no little box in the bottom right angle of the triangle, so there's no way to know it's a 90 degree angle without knowing the values of the other two angles...and you didn't give the measurement of the top right one :/
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