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TrongaMonga · 05-08-2006, 01:02 PM

It would depend on the signal of the last element of the sum.

But we'd have to have (how do you write polynomion, or whatever

, btw?) a pair of +1 with -1 for that to equal zero.

That is, we'd need

0=1-1+1-1+1-1+...1-1+1-1+1-1
RHS=1-(1-1)-(1-1)-(1-...1)-(1-1)-(1-1)-1

05-08-2006, 01:02 PM	#5 (permalink)
TrongaMonga Grumpy Old Grandpa Join Date: Dec 2002 Location: Portugal Age: 23 Posts: 10,005	It would depend on the signal of the last element of the sum. But we'd have to have (how do you write polynomion, or whatever , btw?) a pair of +1 with -1 for that to equal zero. That is, we'd need 0=1-1+1-1+1-1+...1-1+1-1+1-1 RHS=1-(1-1)-(1-1)-(1-...1)-(1-1)-(1-1)-1 __________________ National Anthem and english translation SkuZZy, you won't be forgotten. \| Theroy, I want your babies. Maverick, wish you and Shayne a great life. \| TheSummit, if you weren't European... RyanXWing & Billy the Overlord, <3 \| coolmission, get some new boots, puss'. Master of Disaster \| Fire Lord \| Prophet of Insanity Last edited by coRtALoS: 06-07-2004 at 04:25 PM. Reason: coRtamination is a plague, I'm afraid